86 lines
2.4 KiB
Bash
Executable File
86 lines
2.4 KiB
Bash
Executable File
#!/bin/bash
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# 获取当前日期和时间
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current_time=$(date +"%Y%m%d%H")
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userName=$1
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password=$2
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dbName=$3
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host=$4
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backUpPath=$5
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ossPath=$6
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# 备份文件名
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backup_file="${dbName}_backUp_${current_time}.sql"
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echo "backup_file: "${backup_file}
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mkdir ${backUpPath} -p || true
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# 备份MySQL数据库
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mysqldump --column-statistics=0 -R --opt -u${userName} -p"${password}" -h${host} ${dbName} > ${backUpPath}/"$backup_file"
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cd ${backUpPath}
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rm sql -rf || true
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mkdir sql || true
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mv ${backup_file} sql/
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tar -czvf ${backup_file}".tar.gz" "sql/"
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ossutil cp ${backup_file}".tar.gz" oss://${ossPath}/${backup_file}".tar.gz"
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rm -fr sql
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calculate_hour_diff() {
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# 传入两个时间字符串作为参数
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local time1=$1
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local time2=$2
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# 截取时间字符串中的年、月、日和小时部分
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local year1=${time1:0:4}
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local month1=${time1:4:2}
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local day1=${time1:6:2}
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local hour1=${time1:8:2}
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local year2=${time2:0:4}
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local month2=${time2:4:2}
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local day2=${time2:6:2}
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local hour2=${time2:8:2}
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# 将时间字符串转换为时间戳
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local timestamp1=$(date -d "$year1-$month1-$day1 $hour1:00:00" +%s)
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local timestamp2=$(date -d "$year2-$month2-$day2 $hour2:00:00" +%s)
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# 计算两个时间戳的差值，单位为小时
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local diff_hours=$(( ($timestamp2 - $timestamp1) / 3600 ))
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# 返回计算结果
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echo $diff_hours
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}
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# 存储60个小时前的备份文件名的数组
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old_backup_files=()
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cd ${backUpPath}
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# 遍168个小时前的备份文件，并将文件名存入数组
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CURRENT_DATE=$(date +%Y%m%d%H)
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for file in ${dbName}--*.sql.tar.gz; do
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file_date=$(echo "$file" | grep -oP "\d{10}(?=.sql.tar.gz)")
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if [ ${#file_date} -le 1 ]; then
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continue
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fi
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echo $file_date
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difft=$(calculate_hour_diff $file_date $CURRENT_DATE )
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echo difft $difft
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if [[ difft -gt 168 ]]; then
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echo $file $CURRENT_DATE $file_date $((CURRENT_DATE - file_date))
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old_bacup_files+=("$file")
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fi
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done
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# 遍历数组，删除备份文件
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for file in "${old_backup_files[@]}"; do
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rm "$file" || true
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ossutil rm $file oss://${ossPath}/$file -f || true
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done
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#删除10天前的备份
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#delete_date=$(date -d "10 days ago" +%Y-%m-%d)
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#delete_file="${dbName}_backup_${delete_date}.sql.tar.gz"
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#rm ${backUpPath}/"$delete_file"
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# 输出日志
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echo "[$current_date $current_time] 执行${dbName}数据库备份并删除10天前备份成功"
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