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时间戳和int进行比较问题

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zhangkun9038@dingtalk.com 2025-08-18 02:23:49 +08:00
parent dee9cdb16a
commit b14ed06579
2 changed files with 46 additions and 6 deletions
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15
freqtrade/templates/freqaiprimer.py
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@ -1577,21 +1577,24 @@ class FreqaiPrimer(IStrategy):
trend_scores.append(50)
continue
# 获取时间戳 - 统一使用无时区的时间戳
# 获取时间戳 - 统一使用整数时间戳
try:
last_idx = hist_df.index[-1]
if isinstance(last_idx, pd.Timestamp):
# 确保时间戳是无时区的
# 确保时间戳是无时区的整数
ts = last_idx.tz_localize(None) if last_idx.tz else last_idx
timestamp = int(ts.timestamp())
elif isinstance(last_idx, (int, np.integer)):
# 如果索引已经是整数，直接使用
timestamp = int(last_idx)
elif hasattr(last_idx, 'timestamp'):
timestamp = int(last_idx.timestamp())
else:
# 使用UTC时间避免时区问题
timestamp = int(pd.Timestamp.utcnow().timestamp()) + i
# 使用当前时间的整数时间戳
timestamp = int(pd.Timestamp.utcnow().timestamp())
except Exception as e:
# 使用UTC时间避免时区问题
timestamp = int(pd.Timestamp.utcnow().timestamp()) + i
# 使用当前时间的整数时间戳作为fallback
timestamp = int(pd.Timestamp.utcnow().timestamp())
# 获取趋势得分
score = self.get_trend_score_with_cache(

37
test_timestamp.py Normal file
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@ -0,0 +1,37 @@
#!/usr/bin/env python3
"""
测试时间戳处理的脚本
"""
import pandas as pd
import numpy as np
from datetime import datetime
def test_timestamp_handling():
"""测试时间戳处理逻辑"""
# 创建测试数据
dates = pd.date_range('2024-01-01', periods=100, freq='1min')
df = pd.DataFrame({
'close': np.random.randn(100),
'volume': np.random.randn(100)
}, index=dates)
print("测试数据创建成功")
print(f"数据类型: {type(df.index[0])}")
print(f"索引示例: {df.index[0]}")
# 测试时间戳转换
for i in range(-10, 0):
last_idx = df.index[i]
if isinstance(last_idx, pd.Timestamp):
ts = last_idx.tz_localize(None) if last_idx.tz else last_idx
timestamp = int(ts.timestamp())
print(f"索引 {i}: {last_idx} -> {timestamp}")
else:
timestamp = int(last_idx) if isinstance(last_idx, (int, np.integer)) else int(pd.Timestamp.utcnow().timestamp())
print(f"索引 {i}: {last_idx} -> {timestamp}")
print("时间戳处理测试完成")
if __name__ == "__main__":
test_timestamp_handling()