增量式备份

backup.sh

@@ -1,7 +1,7 @@
 #!/bin/bash
 
 # 获取当前日期和时间
-current_time=$(date +"%Y-%m-%d-%H")
+current_time=$(date +"%Y%m%d%H")
 userName=$1
 password=$2
 dbName=$3
@@ -24,14 +24,51 @@ tar -czvf ${backup_file}".tar.gz" "sql/"
 ossutil cp ${backup_file}".tar.gz" oss://${ossPath}/${backup_file}".tar.gz"
 rm -fr sql
 
+calculate_hour_diff() {
+    # 传入两个时间字符串作为参数
+    local time1=$1
+    local time2=$2
+
+    # 截取时间字符串中的年、月、日和小时部分
+    local year1=${time1:0:4}
+    local month1=${time1:4:2}
+    local day1=${time1:6:2}
+    local hour1=${time1:8:2}
+
+    local year2=${time2:0:4}
+    local month2=${time2:4:2}
+    local day2=${time2:6:2}
+    local hour2=${time2:8:2}
+
+    # 将时间字符串转换为时间戳
+    local timestamp1=$(date -d "$year1-$month1-$day1 $hour1:00:00" +%s)
+    local timestamp2=$(date -d "$year2-$month2-$day2 $hour2:00:00" +%s)
+
+    # 计算两个时间戳的差值，单位为小时
+    local diff_hours=$(( ($timestamp2 - $timestamp1) / 3600 ))
+
+    # 返回计算结果
+    echo $diff_hours
+}
 # 存储60个小时前的备份文件名的数组
 old_backup_files=()
 
 cd ${backUpPath}
 # 遍历60个小时前的备份文件，并将文件名存入数组
-while IFS= read -r -d '' file; do
+CURRENT_DATE=$(date +%Y%m%d%H)
-    old_backup_files+=("$file")
+for file in ${dbName}--*.sql.tar.gz; do
-done < <(find ${backUpPath} -name "${dbName}_backUp_*.tar.gz" -type f -mmin +1440 -print0)
+    file_date=$(echo "$file" | grep -oP "\d{10}(?=.sql.tar.gz)")
+    if [ ${#file_date} -le 1 ]; then
+      continue
+    fi
+    echo $file_date
+    difft=$(calculate_hour_diff $file_date $CURRENT_DATE )
+    echo difft $difft
+    if [[ difft -gt 24 ]]; then
+    	echo $file  $CURRENT_DATE $file_date $((CURRENT_DATE - file_date))
+        old_bacup_files+=("$file")
+    fi
+done
 
 # 遍历数组，删除备份文件
 for file in "${old_backup_files[@]}"; do