每小时上传备份,并删除老的备份

This commit is contained in:
zhangkun9038@dingtalk.com 2023-07-13 16:17:05 +08:00
parent b24ea3c3e3
commit a1f616525c
2 changed files with 25 additions and 10 deletions

View File

@ -8,8 +8,6 @@ dbName=$5
backUpPath=$6
ossPath=$7
protol=oss
PATH=PATH:/usr/bin:/usr/sbin:/usr/local/bin
cd $backUpPath
@ -26,4 +24,4 @@ mv ${dbName}.sql sql
tar -czvf ${dbName}.sql.tar.gz sql
echo "ossPath: "${ossPath}
ossutil cp ${dbName}.sql.tar.gz ${protol}://${ossPath}/ -f
ossutil cp ${dbName}.sql.tar.gz oss://${ossPath}/ -f

View File

@ -1,8 +1,7 @@
#!/bin/bash
# 获取当前日期和时间
current_date=$(date +%Y-%m-%d)
current_time=$(date +%H:%M:%S)
current_time=$(date +"%Y-%m-%d-%H")
userName=$1
password=$2
dbName=$3
@ -10,7 +9,8 @@ host=$4
backUpPath=$5
# 备份文件名
backup_file="${dbName}_backup_${current_date}.sql"
backup_file="${dbName}_backUp_${current_time}.sql"
echo "backup_file: "${backup_file}
mkdir ${backUpPath} -p || true
# 备份MySQL数据库
@ -20,12 +20,29 @@ rm sql -rf || true
mkdir sql || true
mv ${backup_file} sql/
tar -czvf ${backup_file}".tar.gz" "sql/"
ossutil ${backup_file}".tar.gz" oss://${ossPath}/${backup_file}".tar.gz"
rm -fr sql
#
# 存储60个小时前的备份文件名的数组
old_backup_files=()
cd ${backUpPath}
# 遍历60个小时前的备份文件并将文件名存入数组
while IFS= read -r -d '' file; do
old_backup_files+=("$file")
done < <(find ${backUpPath} -name "${dbName}_backUp_*.tar.gz" -type f -mmin +3600 -print0)
# 遍历数组,删除备份文件
for file in "${old_backup_files[@]}"; do
rm "$file" || true
ossutil rm $file oss://${ossPath}/$file -f || true
done
#删除10天前的备份
delete_date=$(date -d "10 days ago" +%Y-%m-%d)
delete_file="${dbName}_backup_${delete_date}.sql.tar.gz"
rm ${backUpPath}/"$delete_file"
#delete_date=$(date -d "10 days ago" +%Y-%m-%d)
#delete_file="${dbName}_backup_${delete_date}.sql.tar.gz"
#rm ${backUpPath}/"$delete_file"
# 输出日志
echo "[$current_date $current_time] 执行${dbName}数据库备份并删除10天前备份成功"